This is the trick.
- Find the sums of alternate digits
- Find the difference between the two sums
- If that difference can be divided by 11without a remainder, the original number is also divisible by 11
Here let us find the sums of alternate digits.
- 5+8+2=15
- 3+1=4
- Difference=15-4=11
- 11 is divisible by 11. So 53812 is also divisible by 11.
Let us find the sums of alternate digits
- 5+8+8+6=27
- 4+0+1=5
- Difference=27-5=22
- 22 is divisible by 11; so is 5480816
Let us find the sums of alternate digits
- 3+9+7=19
- 4+8+5=17
- Difference=19-7=2
- 2 is not divisible by 11. So 349875 can not be divided by 11 without leaving a remainder.
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